pu ekot
12-01-2006, 12:36 AM
Okay, the previous thread was locked, presumably because of my intermitent fits of rage(props to the mods for putting up with that and not banning me). So let's discuss this honestly, no more name calling, no more craziness. Here is the important part of my previous posts:
People who disagree with me, tell me, specifically, what part you are confused with, and I will do my best to explain it to you.
Let's define potency. Potency(percent) = amount of active chemical(grams)/total amount of substance (grams)
We can all agree honey oil is more potent than regular bud, because there is alot of THC over less material. Let's say regular put is 5% potency, and honey oil is 50%. I know these are incorrect, they are just to prove my theory. So lets say you take 60 grams of dry bud, and divy it up into 3 groups of 20 grams. There is 1 gram of THC in each group of bud, making it 5% potency (1/20=0.05=5%). Now you make honey oil with one group(let's pretend this is a lossless process), and you end up with only 2 grams of total material, one of which is THC. That means your honey oil is 50% potency (1/2=0.5=5%). Now you water cure one group, and loose 10 grams of shit in the water. That means you end up with only 15 grams of water-cured bud, but it's 10% potency(1/10=0.1=10%). Let's see what our three groups are like now:
weight thc potency
Regular bud 20g 1g 5%
Water-cured 10g 1g 10%
Honey oil 2g 1g 50%
As you can see, we have not magically gained any THC, there is no voodoo going on. The water cured is more potent than the regular bud, but you still only have 1g of THC.
Now, ask your questions, I'll do my best to explain them.
People who disagree with me, tell me, specifically, what part you are confused with, and I will do my best to explain it to you.
Let's define potency. Potency(percent) = amount of active chemical(grams)/total amount of substance (grams)
We can all agree honey oil is more potent than regular bud, because there is alot of THC over less material. Let's say regular put is 5% potency, and honey oil is 50%. I know these are incorrect, they are just to prove my theory. So lets say you take 60 grams of dry bud, and divy it up into 3 groups of 20 grams. There is 1 gram of THC in each group of bud, making it 5% potency (1/20=0.05=5%). Now you make honey oil with one group(let's pretend this is a lossless process), and you end up with only 2 grams of total material, one of which is THC. That means your honey oil is 50% potency (1/2=0.5=5%). Now you water cure one group, and loose 10 grams of shit in the water. That means you end up with only 15 grams of water-cured bud, but it's 10% potency(1/10=0.1=10%). Let's see what our three groups are like now:
weight thc potency
Regular bud 20g 1g 5%
Water-cured 10g 1g 10%
Honey oil 2g 1g 50%
As you can see, we have not magically gained any THC, there is no voodoo going on. The water cured is more potent than the regular bud, but you still only have 1g of THC.
Now, ask your questions, I'll do my best to explain them.