Is this calculation correct ?
My grow is 160m3. Its a sealed environment since last week. I need to use co2. I also need to decide which generator to buy. I've decided to go the propane route. Considerations here are the large amount of heat generated by a propane burner and the quantity of co2 produced.
There is a generator on the market rated at 4kW and producing 0.9Kg of co2 per hour. Now 1 Kg of co2 has a volume of 0.509 m3, therefore this gen. will produce 0.458m3/hr. of co2. Now how long will it take to raise the quantity of co2 in the grow to 1800ppm given no leaks and no consumption of co2 ?
O.K., so 1 ppm is one-part-per-million. Now 1 ppm of my 160m3 grow is
0.00016 m3. Therefore 0.458/0.00016 = 2862.5 ppm of co2 should be in the grow after one hour assuming no loss/consumption. The length of time therefore to bring the grow to 1800ppm is about 37 mins with this generator. Assuming a starting point of about 400ppm before co2 injection, the real time therefore would be about 30 mins.
Is this correct folks ???
Now, the thing I haven't a clue about is the consumption. I'll be growing 200 plants aeroponically which will feed off the co2. Given no leaks, my big question is : Does this gen. have the capacity to keep my grow at 1800ppm ?
Grow temp will be 27deg. C.

No guessing please !! I don't want to waste money on a gen. that is under-powered and I'll be struggling to have even 400ppm in the room.....I'd sure appreciate the opinions of people who are using co2.
houdini Reviewed by houdini on . Calculating co2 requirements for a sealed grow Is this calculation correct ? My grow is 160m3. Its a sealed environment since last week. I need to use co2. I also need to decide which generator to buy. I've decided to go the propane route. Considerations here are the large amount of heat generated by a propane burner and the quantity of co2 produced. There is a generator on the market rated at 4kW and producing 0.9Kg of co2 per hour. Now 1 Kg of co2 has a volume of 0.509 m3, therefore this gen. will produce 0.458m3/hr. of co2. Now how Rating: 5