E/I = R (rounding to 2 places cause of the tolerances)

So to drop:
.5 volt at 1.2A we need .5/1.2 = .42 ohm resistor
.4V...................................... .33
.3V..................................... .25
.2V..................................... .17

Radio shack's got .47 ohm, 5 watt resistors. And I've got some 1 ohm around here somewhere.

R1 x R2
--------- = R total
R1 + R2

so a .47 parallelled with a 1.0 gives .32 Ohm. Two .47's would give .235 ohm. Gotta get to Rat Sack before they close-- I can figure out how to combine them to get what I need by using THE LAW. :dance::clap::woohoo: Thanks Weezard!!!!