Calling out to Weezard for LED advice

[Weezard]

Weezard, how did you arrive at this? As I said before, I'm not sure which terms to plug into the equation.

The answer is quite simple.
I screwed up.
Must have been too early.:stoned:
Happens alla time.
Sorry.

So, let's see if I can still figger.
Um.

R = E/I
So, .4/1.2 = .334 Should be .33 ohms. .34 is close enough and can be cobbled from 2 .68 ohm resistors in parallel.

Here's where I got bumfoozled.
P = E x I .4 x 1.2 = .48 W
A couple 1 or 2 Watt .68 ohm should run cool enough.

Let that be a lesson to ya.
If ya want math done right, yer gonna have to DIY.
There is no "I" in Weezard.

Oddly unabashed,
Wee Zard