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12-04-2008, 09:12 PM #11OPSenior Member
First attempt at a 24-hour "Martian Method"
Originally Posted by salmayo
Originally Posted by salmayo
Originally Posted by salmayo
Originally Posted by salmayo
Originally Posted by salmayo
Originally Posted by salmayo
I don't know what the time factor is for the combination of light that I'm using, but I'm pretty sure that 50 watts of 660 LED and 50 watts of RedInc together have a factor larger than 1.333, so I chopped two more hours off the Martian Night and added them to SID, so my new schedule is:
10 hours daylight
5 hours Martian night
8 hours SID
1 hour Martian night
Which means I need a time factor of 1.5 from my night spectrum. The math goes like this:
12 hours SID necessary for flowering
-8 hours SID that I now have
= 4 hours SID that need to happen
I have 6 hours (5+1) of AD instead of 4 hours SID, so:
6 / 4 = 1.5
Which means I need my 6 hours of AD light to have a time factor of 1.5 in order to be equivalent to 4 hours of SID. If my plants start flowering, I know that my factor is 1.5 or less, and I'll lengthen the Martian Night (and shorten the SID time) 15 mins at a time to see what the factor actually is. If they don't start flowering, I'll move it the other way and find out what the factor is there.
If I wanted to work the other way, from a known-time-factor spectrum to decide on a schedule, the math would work out like this:
My AD spectrum does have a lot of 660 LED Red which is very slow (probably much more than 2) but it's countered by the RedInc which are much faster (probably less than 1.5), so for this example let's assume it has a factor of 1.8.
Once I've decided on how much daytime and nighttime I want (my choice was 10 hours daytime and 14 hours total nighttime, which I chose out of thin air for this example) I used this equation to figure out how much SID vs AD time I'd need:
SID = ((12*ADR) - TN) / (ADR-1))
ADR = Artificial Darkness Rate, in this case 1.8
TN = Total Nighttime hours, in this case 14
So
SID = ((12*1.8) - 14) / (1.8-1))
SID = ((21.6) - 14) / (.8))
SID = 7.6 / .8
SID = 9.5 hours, which means 4.5 hours of AD time to total 14 hours of nighttime
To check the math:
4.5 hours of AD time divided by 1.8 means we get 2.5 hours of "SID-equivalent work" done in our 4.5 hours of slower AD time.
2.5 hours of "SID-equivalent work" + 9.5 hours of real SID time = 12 hours of real SID work!
If my math here confuses you, just think about it logically. There are 4.5 hours of AD time happening, but they're running slower than SID time, so you're going to need a bigger amount of AD time to replace a smaller amount of SID time. Our AD time (4.5) is bigger than the SID time we're replacing (2.5), so it makes sense.
Originally Posted by salmayo
Thanks again Sal for all your input/info/corrections!
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