Will someone help me with some math problems?

[rebgirl420]

Yeah like these

[420_24/7]

omg, cats, so cute

[r0k]

^ hahahahaha AH HA! See!!!! Someone else agrees!

Okay folks, take a stab at these if you want

(a) 7x + 2y = 6
(b) 1/2 y + x = -4
(c) If 3x = 4y + 12 find y when x = 0
(d) If a line passes through (-5, 0) and (0, 2), then it passes through all but which quadrant?

Yeaah, we'd need more info to solve a and b.

[420_24/7]

do you have any more of those, reb, im gonna send a bunch of em to my friend

[smoke_and_fly]

im ok at math not the greatest
i was always in top classes at school but algebra is a waste of time
peace

[MadSativa]

guys math is the a begening to all science, but I know how it is to get realy frustrated with math problems, so I can relate. I use algebra every day, and geometry. Just remember all these problems have answers, so their easy you just have to work em.

[Mississippi Steve]

guys math is the a begening to all science, but I know how it is to get realy frustrated with math problems, so I can relate. I use algebra every day, and geometry. Just remember all these problems have answers, so their easy you just have to work em.

Anybody who builds a spreadsheet workbook in Excel is using some serious algebra, and formulas to interconnect the pages, and entries on the pages.

[couch-potato]

No offense to anyone in here, but I found amusement in the thought that a pretty girl could get random people to do her math homework for her over the internet. Not that Cann.com is full of friendly people, but the concept of it is comic gold to me.

[expandingeye]

i am just curious how far into the course you are?
cause im taking algebra for like the 5th time, first time in college though, and those problems all seem like basic algebra we went over weeks ago.

[jakez]

If you're having trouble with the problems you could try finding websites online that teach it in a different/interesting/easier way, I am sure there are millions of them, all it takes is the right method to make it all *click*