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07-08-2007, 07:49 AM #1
OPSenior Member
Anyone have a formula for....
Anyone have a formula for loss of lumens due to distance? I found one that I'm not quite sure about.
davejohnwright Reviewed by davejohnwright on . Anyone have a formula for.... Anyone have a formula for loss of lumens due to distance? I found one that I'm not quite sure about. Rating: 5
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07-31-2007, 02:57 AM #2
Senior Member
Anyone have a formula for....
SCROG bitches
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08-05-2007, 09:23 AM #3
OPSenior Member
Anyone have a formula for....
Damn, that makes it sound only practical to have plants up to about 2.5 feet tall. That means my dreams of having 8 foot + tall plants is gonna require a ton of supplemental lighting on the lower branches to get em' big without sacrificing quality.
Originally Posted by Alaric
Back to the drawing board, and I gotta pick up a ton more flouros than I hoped. Fuck it, good things require the extra effort!
peace
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07-08-2007, 12:13 PM #4
Senior Member
Anyone have a formula for....
Morning Dave-
It's a function of the inverse square law. Here's the math, as we know you love numbers
Sorry, couldn't seem to get a clearer thumbnail. ( Note- edited to include better thumbnail)
Chart looks bout right to me. Don't forget to allow for reflection- inverse square is only a clean calculation if there's no reflective light. If you were to build the space up and then sample w/ a light meter, you'd find that the math holds good until the plane where reflective intersects direct, @ which point they reinforce. You'll find smaller than predicted loss of intensity as you move lower in the space- still there, but the loss ceases to be purely porportional and becomes somewhat fractional, as the level of reflective has an inverse relationship with the level of direct.
Intensity i @ distance r=I assume you understand that we have options on your time,
And we will ditch you in the harbour if we must-
But if it all works out nicely,
You\'ll get the bonus you deserve
From doctors we trust.
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07-08-2007, 05:16 PM #5
Senior Member
Anyone have a formula for....
here's the short, simple version, for us dumb guys: "the closest the plant can get to the light without heat damage, the fastest the plant grows"
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07-08-2007, 10:27 PM #6
OPSenior Member
Anyone have a formula for....
Thanks Rhizome, I'm trying to rethink how tall I can let plants get under my light without the bottom branches getting to little light.
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07-09-2007, 01:55 AM #7
Senior Member
Anyone have a formula for....
A good parabolic reflector helps
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07-12-2007, 02:51 AM #8
OPSenior Member
Anyone have a formula for....
Im gonna save a buck and use the hood I already have. Besides a 1000w puts off alot of heat, and I've never seen an air cooled parabolic.
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07-12-2007, 05:28 AM #9
Senior Member
Anyone have a formula for....
Buy yourself a nice cheap handheld temp gun....tell you exactly how close you can put your light to keep leaf surfaces under 80 degress....which I am told is optimum.
PS...I'm told by the same source....(who knows his shit btw) that that is how the "pros" do it......with a light meter and temp gun which will tell them max watts per sq foot so I'm not sure there is "one" right formula for plants.
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07-14-2007, 03:11 AM #10
Senior Member
Anyone have a formula for....
Note one way to suck heat off a parabolic is to place alm. vent at the top of the fixture and use a bathroom 70 cfm to pump out the extra heat.
I used on with a suncircle with a 1000 watt MH and a 400 watt hps. The vent temp was about 15 degrees differance between room temp and venting temp.
The room was about 20% less time on a normal venting time.
I use a single bulb system now, as very little co2 get picked up by the vertical heat rising from the bulb. The tanks last about the same amount of time. A extra advantage to the heat pump is it warms up the grow room and clone space.
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