OK, yeah I tried to edit but I couldnt. Guess I'm slow...

Quote Originally Posted by zarathustra
i've been thinking, and the guy that planned for the 10" ball's math is off. that is all.
V = 4/3 * pi * r^3

1" sphere--> 4/3 * pi * 1/2 ^ 3 = 1/6 * pi or about 1/2 cu. in.
10" sphere--> 4/3 * pi * 5^3 = 166.666667*pi or about 520 cu. in.

Unless 1/2 * 10 = 520 I don't think his math is correct either