Incidentally, just for those who are curious, we can derive a more reasonable amount weed needed for an LD-50 dose. According to this MSDS for tetrahydrocannabinol, the LD-50 for rats is 666 mg/kg of body weight. If we extrapolate that to humans (probably not terribly accurate, but good enough for a first-order approximation), it would require a 200-pound man (91 kg) to ingest 60,606 mg of THC. The very best weed out there is about 27% THC b.w., which means he'd have to eat 224 grams or nearly a half pound of the stuff. While this may seem low, remember we're extrapolating from rat data, so the actual number for humans may be much higher, and this is also assuming 100% efficiency at extracting the THC during digestion, which would not be the case in reality. I suspect that much roughage would cause considerable gastric upset which would drastically lower the extraction efficiency, as well. I've never heard of anyone eating that much weed at once, in any case. LD-50 data for smoking is not available and would likely be very different from oral ingestion.
