Al-Qaeda invites online questions
An internet message reportedly from al-Qaeda has issued an open offer to people to submit questions online for Osama bin Laden's deputy, Ayman al-Zawahiri.
People are invited to pose questions to Mr Zawahiri in writing via two websites before 16 January. Both media organisations and individuals can take part, a statement on an Islamist website said.
The statement, the authenticity could not be verified, asks media groups to identify themselves and said queries will be sent without any changes to Zawahiri.
In his last message issued earlier this month, the al-Qaeda number two criticised the US-sponsored Middle East peace conference in Annapolis, where a formal negotiations process was agreed to in the Israeli-Palestinian conflict.
RTÃ? News: Al-Qaeda invites online questions
I would just LOVE to see one of these conspiracy "journalists" pose questions regarding 9-11! Here's a challenge to you Alex Jones fans.....make it known to this "hero" that Zawahiri is a available for questions. I'm SURE he'll deem this as being a false site ran by the CIA. LOL
Just imagine on how something like this could ruin sales..........LMAO!!!!
Have a good one!:s4:
Al-Qaeda invites online questions
Al-CIA-Duh. That's right, the CIA created al Qaeda. I listen to Alex Jones from time to time. I think prison planet and AJ is a relatively reliable source of information. I also listen to a lot of other view points. I cross reference to sift through hyperbole. I don't believe everything I hear.
Al-Qaeda cleric exposed as an MI5 double agent
Al-Qaeda invites online questions
Dear Al Qaeda,
Why are your penises SOO much smaller than ours?
*FedEx guy knocks on door
KA_BOOM!
"....but I guess that it comes, with the territory. An ominous landscape of, never-ending calamities'' -Incubus 'Pardon Me'
Al-Qaeda invites online questions
Dear Mr Zawahiri,
Please send me your address. I'd like to to send you a brand new rubber tire for your mother, as the one that she swings on is starting to fall apart.
P.S. Go fuck yourself.